Self-Assessment Solutions

Forces

1.	–176.24lbs
1.	4.54kg
1.	111.2N
4.	460.45N
5.	FS = –mSN = –0.3(460.45) = –138.13N and FK = –mKN = –0.25(460.45) = –115.11N
6.	Fnet = [369.7 0]
7.	The answer is shown in Figure 11.9. Figure 11.9. The free-body diagram for question 7.
8.	Fnet = [88.05 0]

Using Newton's Laws to Determine How Forces Affect an Object's Motion

1.	In the same place
2.	5m/s @ 45°
3.	a = [12.32 0]
4.	154m
5.	a = [6.05 –10.48]
6.	Dr = [27.22 –47.15]